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PMAN 639 PROJECT QUALITY MANAGEMENT FINAL EXAM
Please answer the following True or False questions (each worth 2 points)
A process in control does not produce unacceptable output.
True ______ False___FALSE___
Random variation falls within the control limits.
True ___TRUE___ False______
A process is capable if the variations fall within the control limits.
True ___TRUE___ False______
If X bar chart is in controlthen R chart is also in
True __TRUE___ False________
Control charts are used to determine if there are unexpected changes in the process.
True ___TRUE___ False______
For defective units situations, aP chart is used when the sample size varies.
True ___TRUE___ False______
A standard Six Sigma Process has a 4.5 Sigma performance
True __TRUE___ False________
A process is not capable if the variations exceeds the mean
True ___TRUE___ False______
A histogram shows the trendline of a process
True _____ False____FALSE____
A Fishbone diagram used to organize data in categories
True ___TRUE__ False________
Please answer the following multiple choice questions (each worth 4 points)):
1) Which of the following tools is used to identify process frequency distribution?
- A) Matrix diagram
- B) Histogram
C)Pareto Chart
- D) Check sheets
- E) Process map
2) Which of the following tools is used to organize ideas.
- A) Matrix diagram
- B) Histogram
- C) Affinity Diagram
- D) Check sheets
- E) Process map
3) Which of the following tools is used to analyze cycle time
- A) Control Chart
- B) Fishbone diagram
- C) Pareto Chart
- D) Process map
- E) Root Cause Analysis
4) Which of the following is true of common cause variation?
- A) It is uncontrollable.
- B) It is centeredaround the mean.
- C) It is inherent in the process.
- D) All of the above.
- E) None of the above
5) A true 3 Sigma Process should not havemorethan_______defects per million opportunities
- 3.4
- 270
- 2700
- 45500
Please respond to the following questions. Each question is worth 10 points:
1) 97.
1) Please create a process map for withdrawing cash from an ATM machine as described below:
Janet needed some cash and walks up to an ATM machine. She inserts her debit card. The machine returns the card and the monitor reads: “could not read the card try again”. Janet recognizes that she has entered the card in the wrong direction. She takes the card and turns it around and insert the card again. The machine keeps the card and the monitor reads: “enter pass code”. Janet enters a 4 digit code. The monitor reads: “ error, try again”.
Janet enters the code again. The monitor displays: Withdrawal? Yes No
Janet selects Yes. Displays shows:
“ $100, $200, $300, $400, $______”.
Janet selects $200. The machine pushes out 10 $20 bills. Monitor then displays “Receipt? Yes No”. Janet selects No. Monitor displays “Take your cash” .
The machine returns the card. Display changes to “Thank You”.
Janet takes the cash and her card and walks away.
2)
A customer relationship manager decided to track customer complaints as part of his ongoing customer satisfaction improvement program. After collecting data for 3 months, their check sheet appears as follows:
Type of Problem Frequency
(number of times)
Call went to voice mail 18
Items damaged when received 15
Literature not in the box 7
Parts missing 13
Billing error 6
Unit not working 2
Delivery was late 3
Construct a Pareto chart including the cumulative % frequency.What is the cumulative percentage of the two highest priority issues?
3) A quality control engineer monitors the quality of a cylinder production line. He regularly selects a sample of 5 units and measures the diameters. The specification requires the diameter to be 6 inches plus/minus 0.1 inch. The following is a record of the measurements. Is the production process in control? Please use X bar and R charts to make an assessment.
Sample item 1 item 2 item 3 item 4 item 5
1 6.10 6.15 5.35 5.98 5.95
2 6.35 6.02 6.20 6.10 5.70
3 5.85 5.90 6.20 6.12 6.08
4 6.00 5.80 5.70 6.04 6.17
5 6.15 5.60 6.25 5.99 6.01
6 6.13 6.05 5.89 6.00 5.87
7 5.88 6.03 5.76 6.1 3 6.00
8 6.12 5.45 6.15 6.04 5.91
Sample Task1 Task2 Task3 Task4 Task5 total x bar R
1 6.1 6.15 5.35 5.98 5.95 29.53 5.906 0.8
2 6.35 6.02 6.2 6.1 5.7 30.37 6.074 0.65
3 5.85 5.9 6.2 6.12 6.08 30.15 6.03 0.27
4 6 5.8 5.7 6.04 6.17 29.71 5.942 0.47
5 6.15 5.6 6.25 5.99 6.01 30 6 0.65
6 6.13 6.05 5.89 6 5.87 29.94 5.988 0.26
7 5.88 6.03 5.76 6.13 6 29.8 5.96 0.37
8 6.12 5.45 6.15 6.04 5.91 29.67 5.934 0.7
Sum= 47.834 4.17
average= 5.97925 0.52125
We have from calculation table
= 5.97925
= 0.52125
R CHART
Centreline == 0.52125
Upper Class Limit =UCL = D4 * =2.114*(0.52125) = 1.1019225
Lower Class Limit =LCL = D3 * = 0*(0.52125) = 0
X – bar CHART
Centreline= = 5.97925
Upper Class Limit =UCL = + A2( )
= 5.97925 + 0.577* (0.52125)
= 5.97925 + 0.030076125
= 6.28001125
Lower Class Limit =LCL = – A2( )
= 5.97925 – 0.030076125
= 5.67848875
4) For the above problem if the true mean and standard deviation of the process are 6.05 and 0.04,
- Is the process capable of meeting its specification? Calculate its CP and CPk.
The process is capable of meeting the specification laid out.
Cpk = min(USL – μ, μ – LSL) / (3σ)
Cpk=min(6.28001125-0.1, 0.1-5.67848875)/3×0.04
Cpk=
1.068
- What % of the cylinders if any are out of specs?
4.6%
5) A project manager at Global Design Corporation has collected the following data on the size of software programs and the length of programming time. The company is bidding on a new system that is estimated to consist of 300,000 lines of code. Use the data to find the correlation function of coding time to the program size and estimate the number of days it would take to code the system.
Module Size in 1000 lines of code (KLOC)
X
Number of days to code
Y
SQUARE OF X SQUARE OF Y
1 160 70
2 158 66
3 150 70
4 135 59
5 178 72
6 170 63
7 158 69
8 138 65
9 200 72
10 195 68
11 189 65
12 173 68
13 159 70
14 163 55
15 150 66
16 140 65
17 206 73
18 144 64
19 157 70
20 183 74
21 195 75
22 190 77
23 182 69
24 152 65
25 174 69
We should apply Pearson’s correlation coefficient in the following question
Module Size code (KLOC), x Number of codes, y X^2 Y^2 XY
1 150 72 22500 5184 (150*72) =10800
2 158 66 24964 4356 (158*66) =10428
3 148 65 21904 4225 (148*65) =9620
4 120 60 14400 3600 (120*60) =7200
5 178 75 31684 5625 (178*75) =13350
6 170 68 28900 4624 (170*68) =11560
7 152 68 23104 4624 (152*68) =10336
8 138 65 19044 4225 (138*65) =8970
9 200 80 40000 6400 (200*80) =16000
10 195 75 38025 5625 (195*75) =14625
11 189 65 35721 4225 (189*65) =12285
12 173 68 29929 4624 (173*68) =11764
13 159 62 25281 3844 (159*62) =9858
14 163 71 26569 5041 (163*71) =11573
15 150 65 22500 4225 (150*65) =9750
16 140 65 19600 4225 (140*65) =9100
17 206 74 42436 5476 (206*74) =15244
18 144 64 20736 4096 (144*64) =9216
19 157 70 24649 4900 (157*70) =10990
20 183 76 33489 5776 (183*76) =13908
21 195 75 38025 5625 (195*95) =14625
22 190 77 36100 5929 (190*77) =14630
23 185 73 34225 5329 (185*73) =13505
24 152 58 23104 3364 (152*58) =8816
25 178 70 31684 4900 (178*70) =12460
Sum 4173 1727 708573 120067 290613
m = 0.1949227
A project manager has developed the following data on a
project tasks and durations by weeks.
Please create an AON diagram, identify the critical path and the expected project duration.
What is the chance of completing the project one week earlier than expected?
The customer has asked for a 99% confidence on the project completion date. Calculate the number of additional weeks the project manager needs to make that commitment.
Time estimation in weeks
Task Predecessor optimistic Most likely Pessimistic
A 3 4 5
B A 1 8 15
C A 2 4 6
D A 4 8 12
E B 7 9 11
F C,B 2 5 8
G E,D 6 8 10
H F,G 4 7 10
Activity expected time variance
A 4 0.11
B 8 5.44
C 4 0.44
D 8 1.77
E 9 0.44
F 5 1
G 8 0.44
H 7 1
D G
A B E H
C
Path duration
ADGH 4+8+8+7=27
ABEGH 4+8+9+8+7=36
ABFH 4+8+5+7=24
ACFH 4+4+5+7=20
Critical Path take the longest path= 36
Expected completion of the project = 36 weeks
It takes one week to have less time =36-1. To be 35 weeks. The variance of activities =0.11+5.44+0.44+0.44+1= 7.43
Standard deviation would be = 2.723
Z score would be 35-36/2.723 = -0.37
From table probability would be= 0.35569
Which is the same as 35.569